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Article ID: 1028
Last updated: 05 Feb, 2008
Problem
The
Action
Try using the following workaround to this problem:
The
isShown() member function does not seem to work correctly.Action
Try using the following workaround to this problem:
if( IsWindowVisible( *pButton1 ) )
instead of
if(pButton1->isShown())
You can substitue any control that the isShown() function is valid for. For example:
if( IsWindowVisible( *dlg ) )
instead of
if(dlg->isShown())
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Article ID: 1028
Last updated: 05 Feb, 2008
Revision: 1
Views: 2694
Posted: 15 Jun, 1998 by
Dean J.
Updated: 05 Feb, 2008 by
Dean J.
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